November 27, 2015

How to pass multi parameter in RestSharp body

private RestClient clientV;
_clientVideo = new RestClient("<Rest API url>");

RestRequest request = new RestRequest(Method.POST)
{
Resource = "<Make your resource url>",
RequestFormat = DataFormat.Json,
};

request.AddBody(new
{
   Item1 = Value1,
   Item2 = Value2,
   Item3 = Value3

});
var response = clientV.Execute(request) as RestResponse;

That's it.
Enjoy Learning.

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